extreme f(x)=x^2+(360)/x

Lösung

extrempunkte

f (x) = x^{2} + \frac{360}{x}

Minimum (3180, 18 0^{\frac{2}{3}} + \frac{72 \cdot 5 ^{\frac{2}{3}}}{3 36})

Schritte zur Lösung

f^{'} (x) = 2 x - \frac{360}{x ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Absteigend

: 0 < x < 3180,

Ansteigend

: 3180 < x < \infty

Stecke

x = 3180

x^{2} + \frac{360}{x} : 18 0^{\frac{2}{3}} + \frac{72 \cdot 5 ^{\frac{2}{3}}}{3 36}

Minimum (3180, 18 0^{\frac{2}{3}} + \frac{72 \cdot 5 ^{\frac{2}{3}}}{3 36})

e x t re m e p (a, b) = (a \cdot e) - 2200 - 0.02 \cdot e - b

e x t re m e 7 x (1 + 12 x^{2})^{- 2}

e x t re m e f (x) = 4 sin (x) + 3 cos (x), 0 \leq x \leq 2 π

e x t re m e f (x, y) = 2 x^{2} + 4 x y - x^{2} y - 4 x

e x t re m e f (x) = y e^{x} + x y^{2}