What is the extreme f(x)=-x^3+3x+5 ?

The extreme f(x)=-x^3+3x+5 is Minimum(-1,3),Maximum(1,7)

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extreme f(x)=-x^3+3x+5

extreme points

f (x) = - x^{3} + 3 x + 5

Minimum (- 1, 3), Maximum (1, 7)

Solution steps

f^{'} (x) = - 3 x^{2} + 3

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x + 5 : 3

Minimum (- 1, 3)

Plug

x = 1

into

- x^{3} + 3 x + 5 : 7

Maximum (1, 7)

Minimum (- 1, 3), Maximum (1, 7)

E (a, b) = \frac{a ( a + b ) ^{2} ( a - b )}{a ^{2} - b ^{2}}

f (x) = (x^{2} - \frac{7}{3} x + \frac{13}{9}) e^{3 x}

f (x) = 2 x^{5} + 2 x^{4} - x^{3} + 6 x^{2} + 8 x + 4

f (x) = \frac{- 1}{x - 4}

x^{3} - 3 x^{2} + 2 x + 8

What is the extreme f(x)=-x^3+3x+5 ?
The extreme f(x)=-x^3+3x+5 is Minimum(-1,3),Maximum(1,7)