What is the extreme f(x)=x^3-7x^2+15x-9 ?

The extreme f(x)=x^3-7x^2+15x-9 is Maximum(5/3 , 32/27),Minimum(3,0)

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extreme f(x)=x^3-7x^2+15x-9

extreme points

f (x) = x^{3} - 7 x^{2} + 15 x - 9

Maximum (\frac{5}{3}, \frac{32}{27}), Minimum (3, 0)

Solution steps

f^{'} (x) = 3 x^{2} - 14 x + 15

Find intervals:

Increasing

: - \infty < x < \frac{5}{3},

Decreasing

: \frac{5}{3} < x < 3,

Increasing

: 3 < x < \infty

Plug

x = \frac{5}{3}

into

x^{3} - 7 x^{2} + 15 x - 9 : \frac{32}{27}

Maximum (\frac{5}{3}, \frac{32}{27})

Plug

x = 3

into

x^{3} - 7 x^{2} + 15 x - 9 : 0

Minimum (3, 0)

Maximum (\frac{5}{3}, \frac{32}{27}), Minimum (3, 0)

f (x) = x^{2} + 2 y^{2} + x^{2} y + 11

f (x, y) = 6 e^{y} - 6 y e^{x}

f (x) = 12 (1 + \frac{1}{x} + \frac{1}{x ^{2}})

sin (2 x), 0 \leq x \leq π

f (x) = 5 x + 3 x^{- 1}

What is the extreme f(x)=x^3-7x^2+15x-9 ?
The extreme f(x)=x^3-7x^2+15x-9 is Maximum(5/3 , 32/27),Minimum(3,0)