What is the extreme f(x)=((x^2-11))/(x-6) ?

The extreme f(x)=((x^2-11))/(x-6) is Maximum(1,2),Minimum(11,22)

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extreme f(x)=((x^2-11))/(x-6)

extreme points

f (x) = \frac{( x ^{2} - 11 )}{x - 6}

Maximum (1, 2), Minimum (11, 22)

Solution steps

f^{'} (x) = \frac{x ^{2} - 12 x + 11}{( x - 6 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 6,

Decreasing

: 6 < x < 11,

Increasing

: 11 < x < \infty

Plug

x = 1

into

\frac{x ^{2} - 11}{x - 6} : 2

Maximum (1, 2)

Plug

x = 11

into

\frac{x ^{2} - 11}{x - 6} : 22

Minimum (11, 22)

Maximum (1, 2), Minimum (11, 22)

y = (x - 4)^{2} (x + 2)^{3}

f (x) = \frac{1}{3} x^{3} - x^{2} - 3 x + 3

f (x) = 5 x^{3} - 30 x^{2} + 45 x

f (x) = x y^{2} - 6 x^{2} - 3 y^{2}

f (x) = 3 x + \frac{1}{x}

What is the extreme f(x)=((x^2-11))/(x-6) ?
The extreme f(x)=((x^2-11))/(x-6) is Maximum(1,2),Minimum(11,22)