extreme f(x)=2x^2+4x-5

解答

极值点

f (x) = 2 x^{2} + 4 x - 5

极小值 (- 1, - 7)

求解步骤

f^{'} (x) = 4 x + 4

Find intervals:

递减

: - \infty < x < - 1,

递增

: - 1 < x < \infty

将

x = - 1

代入

2 x^{2} + 4 x - 5 : - 7

极小值 (- 1, - 7)

e x t re m e f (x, y) = 3 x^{2} + y^{2} - x y - 11 x

e x t re m e f (t) = (t) + 2 u (t) - 3 e^{- 2 t} u (t)

e x t re m e f (x) = (x - 6) e^{x}

e x t re m e f (x) = (x + 14) (x - 7)^{2}

e x t re m e f (x) = x^{3} + 2 x y^{2} - 5 x - 4 y + 20