What is the domain of ln|2x+1|-sin(3x-2) ?

The domain of ln|2x+1|-sin(3x-2) is x -1/2

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domain of ln|2x+1|-sin(3x-2)

domain

ln ∣ 2 x + 1 ∣ - sin (3 x - 2)

x < - \frac{1}{2} or x > - \frac{1}{2}

Solution steps

Find positive values for logs:

x < - \frac{1}{2} or x > - \frac{1}{2}

The function domain

x < - \frac{1}{2} or x > - \frac{1}{2}

e^{x - 1} + 1

3 v^{2} - 75

f (x) = 0.5 (x - 6)^{2} - 3

f (x) = \frac{8 x}{x ^{2} - 2 x - 24}

f (x) = \frac{x ^{3}}{x - 2}

What is the domain of ln|2x+1|-sin(3x-2) ?
The domain of ln|2x+1|-sin(3x-2) is x<-1/2 \lor x>-1/2