What is the domain of f(x)=sqrt(36-x^2)-3 ?

The domain of f(x)=sqrt(36-x^2)-3 is -6<= x<= 6

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domain of f(x)=sqrt(36-x^2)-3

domain

f (x) = 36 - x^{2} - 3

- 6 \leq x \leq 6

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 6

The function domain

- 6 \leq x \leq 6

\frac{1}{x 1 - x ^{2}}

\frac{5 - 2 x}{4 x - 1}

f (x) = - 13 - x

f (x) = \frac{x + 3}{x ^{2} - 6 x - 27}

f (x) = \frac{1}{x ^{2} + 2 x - 3} + x + 2

What is the domain of f(x)=sqrt(36-x^2)-3 ?
The domain of f(x)=sqrt(36-x^2)-3 is -6<= x<= 6