What is the domain of f(x)= 3/(x^2+9)+1/(x^2-1) ?

The domain of f(x)= 3/(x^2+9)+1/(x^2-1) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 3/(x^2+9)+1/(x^2-1)

domain

f (x) = \frac{3}{x ^{2} + 9} + \frac{1}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

3 x^{2} - 5 x + 2

x^{2} - x - ln (x)

f (x) = \frac{- 7 - 6 x}{5 x - 3}

\frac{7 x}{x - 9}

5 x^{3} - 5 x + 1

What is the domain of f(x)= 3/(x^2+9)+1/(x^2-1) ?
The domain of f(x)= 3/(x^2+9)+1/(x^2-1) is x<-1\lor-1<x<1\lor x>1