What is the domain of f(x)=sqrt(4-9x^2) ?

The domain of f(x)=sqrt(4-9x^2) is -2/3 <= x<= 2/3

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domain of f(x)=sqrt(4-9x^2)

domain

f (x) = 4 - 9 x^{2}

- \frac{2}{3} \leq x \leq \frac{2}{3}

Solution steps

Find non-negative values for radicals:

- \frac{2}{3} \leq x \leq \frac{2}{3}

The function domain

- \frac{2}{3} \leq x \leq \frac{2}{3}

- cos (t)

lo g_{10} (\frac{1}{3}) x

f (x) = \frac{( 9 + x )}{e ^{c o s (x)}}

f (x) = (lo g_{2} (x))

\frac{4}{y ^{2} - 4 y + 4}

What is the domain of f(x)=sqrt(4-9x^2) ?
The domain of f(x)=sqrt(4-9x^2) is -2/3 <= x<= 2/3