What is the domain of (sqrt(x^2-2))/(x-2x^2-6) ?

The domain of (sqrt(x^2-2))/(x-2x^2-6) is x = sqrt(2)

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domain of (sqrt(x^2-2))/(x-2x^2-6)

domain

\frac{x ^{2} - 2}{x - 2 x ^{2} - 6}

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

x - 3 - x

\frac{- x + 1}{x ^{2} + 2}

f (x) = - 6 x - 8

f (x) = \frac{x + 3}{x ^{2} - 2 x - 8}

f (x) = (5 x - 25)^{- 2}

What is the domain of (sqrt(x^2-2))/(x-2x^2-6) ?
The domain of (sqrt(x^2-2))/(x-2x^2-6) is x<=-sqrt(2)\lor x>= sqrt(2)