What is the domain of f(x)=(sqrt(2x+14))/(x^2-49) ?

The domain of f(x)=(sqrt(2x+14))/(x^2-49) is -7 7

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domain of f(x)=(sqrt(2x+14))/(x^2-49)

domain

f (x) = \frac{2 x + 14}{x ^{2} - 49}

- 7 < x < 7 or x > 7

Solution steps

Find non-negative values for radicals:

x \geq - 7

Find undefined (singularity) points:

x = 7, x = - 7

Combine real regions and undefined points for final function domain

- 7 < x < 7 or x > 7

f (x) = \frac{5}{x} + \frac{7}{x + 7}

f (x) = \frac{x}{x - 5}

g (x) = \frac{x}{x ^{2} + 15 x + 50}

14 - 2 x

f (x) = \frac{x + 4}{- 2 x - 6}

What is the domain of f(x)=(sqrt(2x+14))/(x^2-49) ?
The domain of f(x)=(sqrt(2x+14))/(x^2-49) is -7<x<7\lor x>7