What is the inverse of sqrt(2x^2-5x-1) ?

The inverse of sqrt(2x^2-5x-1) is (5+sqrt(8x^2+33))/4 ,(5-sqrt(8x^2+33))/4

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inverse of sqrt(2x^2-5x-1)

inverse

2 x^{2} - 5 x - 1

\frac{5 + 8 x ^{2} + 33}{4}, \frac{5 - 8 x ^{2} + 33}{4}

Solution steps

y = 2 x^{2} - 5 x - 1

Replace

x

with

y

x = 2 y^{2} - 5 y - 1

Solve for

y, x = 2 y^{2} - 5 y - 1

\frac{5 + 8 x ^{2} + 33}{4}, \frac{5 - 8 x ^{2} + 33}{4}

f (x) = \frac{( 3 x + 4 )}{x - 2}

f (x) = 4 + 2

y = \frac{( x + 2 )}{x + 7}

\frac{- 2 x - 1}{x - 2}

What is the inverse of sqrt(2x^2-5x-1) ?
The inverse of sqrt(2x^2-5x-1) is (5+sqrt(8x^2+33))/4 ,(5-sqrt(8x^2+33))/4