What is the inverse of 4sin(6/7 x)+5 ?

The inverse of 4sin(6/7 x)+5 is (7arcsin((x-5)/4))/(6)

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inverse of 4sin(6/7 x)+5

inverse

4 sin (\frac{6}{7} x) + 5

\frac{7 arcsin ( \frac{x - 5}{4} )}{6}

Solution steps

Solve for

sin (\frac{6}{7} x), y = 4 sin (\frac{6}{7} x) + 5

sin (\frac{6}{7} x) = \frac{y - 5}{4}

sin (a) = b \Rightarrow a = arcsin (b)

\frac{6}{7} x = arcsin (\frac{y - 5}{4})

Solve for

x, \frac{6}{7} x = arcsin (\frac{y - 5}{4})

\frac{7 arcsin ( \frac{y - 5}{4} )}{6}

Substitute

y = x

\frac{7 arcsin ( \frac{x - 5}{4} )}{6}

- 33

f (x) = \frac{y ^{2}}{72} + \frac{4 y}{36} - \frac{2}{3}

tan (x) - 0.4

f (0) = x^{2} - 2 x + 4

- 25

What is the inverse of 4sin(6/7 x)+5 ?
The inverse of 4sin(6/7 x)+5 is (7arcsin((x-5)/4))/(6)