What is the inverse of 1/2 x^2-2x+1 ?

The inverse of 1/2 x^2-2x+1 is (4+sqrt(8x+8))/2 ,(4-sqrt(8x+8))/2

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inverse of 1/2 x^2-2x+1

inverse

\frac{1}{2} x^{2} - 2 x + 1

\frac{4 + 8 x + 8}{2}, \frac{4 - 8 x + 8}{2}

Solution steps

y = \frac{1}{2} x^{2} - 2 x + 1

Replace

x

with

y

x = \frac{1}{2} y^{2} - 2 y + 1

Solve for

y, x = \frac{1}{2} y^{2} - 2 y + 1

\frac{4 + 8 x + 8}{2}, \frac{4 - 8 x + 8}{2}

f (x) = 3 x^{9} + 6

f (x) = 1.67 \cdot e^{0.2 x}

f (x) = \frac{2 x - 9}{7 x + 3}

\frac{5 x - 5}{3 x - 6}

f (x) = 6 x - 2 + 3

What is the inverse of 1/2 x^2-2x+1 ?
The inverse of 1/2 x^2-2x+1 is (4+sqrt(8x+8))/2 ,(4-sqrt(8x+8))/2