What is the inverse of-0.48x^2+4.8x+3 ?

The inverse of-0.48x^2+4.8x+3 is -(-480+sqrt(-19200x+288000))/(96),-(-480-sqrt(-19200x+288000))/(96)

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inverse of-0.48x^2+4.8x+3

inverse

- 0.48 x^{2} + 4.8 x + 3

- \frac{- 480 + - 19200 x + 288000}{96}, - \frac{- 480 - - 19200 x + 288000}{96}

Solution steps

y = - 0.48 x^{2} + 4.8 x + 3

Replace

x

with

y

x = - 0.48 y^{2} + 4.8 y + 3

Solve for

y, x = - 0.48 y^{2} + 4.8 y + 3

- \frac{- 480 + - 19200 x + 288000}{96}, - \frac{- 480 - - 19200 x + 288000}{96}

f (x) = \frac{7 x}{4 x - 1}

\frac{d}{d} tan (\frac{( 3 )}{3})

y = \frac{6 x + 10}{- 2 - 4 x}

y = lo g_{4} (2 x) - 5

x + 55

What is the inverse of-0.48x^2+4.8x+3 ?
The inverse of-0.48x^2+4.8x+3 is -(-480+sqrt(-19200x+288000))/(96),-(-480-sqrt(-19200x+288000))/(96)