What is the inverse of (2x^2-8x)/(x^2-7x+12) ?

The inverse of (2x^2-8x)/(x^2-7x+12) is (3x)/(x-2)

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inverse of (2x^2-8x)/(x^2-7x+12)

inverse

\frac{2 x ^{2} - 8 x}{x ^{2} - 7 x + 12}

\frac{3 x}{x - 2}

Solution steps

y = \frac{2 x ^{2} - 8 x}{x ^{2} - 7 x + 12}

Replace

x

with

y

x = \frac{2 y ^{2} - 8 y}{y ^{2} - 7 y + 12}

Solve for

y, x = \frac{2 y ^{2} - 8 y}{y ^{2} - 7 y + 12}

\frac{3 x}{x - 2}

lo g_{3} (x) + 2

(x)^{2}

\frac{2 x - 7}{9 - 5 x}

10 - 6 x^{3}

lo g_{2} (4 - x^{2})

What is the inverse of (2x^2-8x)/(x^2-7x+12) ?
The inverse of (2x^2-8x)/(x^2-7x+12) is (3x)/(x-2)