What is the inverse of y=ln((2x-2)/(4-x)) ?

The inverse of y=ln((2x-2)/(4-x)) is -(-2-4e^x)/(e^x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y=ln((2x-2)/(4-x))

inverse

y = ln (\frac{2 x - 2}{4 - x})

- \frac{- 2 - 4 e ^{x}}{e ^{x} + 2}

Solution steps

y = ln (\frac{2 x - 2}{4 - x})

Replace

x

with

y

x = ln (\frac{2 y - 2}{4 - y})

Solve for

y, x = ln (\frac{2 y - 2}{4 - y})

- \frac{- 2 - 4 e ^{x}}{e ^{x} + 2}

ln (x) - 3

y = x^{2} - 16

\frac{6}{( s - 2 ) ^{6}}

f (x) = 1 - 2 2 x + 5

f (x) = lo g_{5} (x - 3)

What is the inverse of y=ln((2x-2)/(4-x)) ?
The inverse of y=ln((2x-2)/(4-x)) is -(-2-4e^x)/(e^x+2)