What is the inverse of f(x)=(2x-3)/(6x-1) ?

The inverse of f(x)=(2x-3)/(6x-1) is (-3+x)/(2(-1+3x))

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inverse of f(x)=(2x-3)/(6x-1)

inverse

f (x) = \frac{2 x - 3}{6 x - 1}

\frac{- 3 + x}{2 ( - 1 + 3 x )}

Solution steps

y = \frac{2 x - 3}{6 x - 1}

Replace

x

with

y

x = \frac{2 y - 3}{6 y - 1}

Solve for

y, x = \frac{2 y - 3}{6 y - 1}

\frac{- 3 + x}{2 ( - 1 + 3 x )}

f (x) = \frac{4 x + 5}{3 x - 8}

f (x) = 4 cos (\frac{x}{3})

f (x) = - 4 lo g_{10} (- \frac{1}{3} (x + 2)) + 1

f (x) = 3 lo g_{6} (x)

e^{x^{2} - 2 x}

What is the inverse of f(x)=(2x-3)/(6x-1) ?
The inverse of f(x)=(2x-3)/(6x-1) is (-3+x)/(2(-1+3x))