What is the inverse of f(x)=(x^2-4)/(x^2+9) ?

The inverse of f(x)=(x^2-4)/(x^2+9) is sqrt((-4-9x)/(x-1)),-sqrt((-4-9x)/(x-1))

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inverse of f(x)=(x^2-4)/(x^2+9)

inverse

f (x) = \frac{x ^{2} - 4}{x ^{2} + 9}

\frac{- 4 - 9 x}{x - 1}, - \frac{- 4 - 9 x}{x - 1}

Solution steps

y = \frac{x ^{2} - 4}{x ^{2} + 9}

Replace

x

with

y

x = \frac{y ^{2} - 4}{y ^{2} + 9}

Solve for

y, x = \frac{y ^{2} - 4}{y ^{2} + 9}

\frac{- 4 - 9 x}{x - 1}, - \frac{- 4 - 9 x}{x - 1}

f (x) = 6 - \frac{1}{2} x

f (x) = \frac{1}{sin ( x )}

f (x) = (x - 3) (x - 5)

f (x) = 1 0^{x + 1}

f (x) = sin (x) + 1

What is the inverse of f(x)=(x^2-4)/(x^2+9) ?
The inverse of f(x)=(x^2-4)/(x^2+9) is sqrt((-4-9x)/(x-1)),-sqrt((-4-9x)/(x-1))