What is the inverse of f(x)= 1/4 (x+3)^2-2 ?

The inverse of f(x)= 1/4 (x+3)^2-2 is 2sqrt(x+2)-3,-2sqrt(x+2)-3

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inverse of f(x)= 1/4 (x+3)^2-2

inverse

f (x) = \frac{1}{4} (x + 3)^{2} - 2

2 x + 2 - 3, - 2 x + 2 - 3

Solution steps

y = \frac{1}{4} (x + 3)^{2} - 2

Replace

x

with

y

x = \frac{1}{4} (y + 3)^{2} - 2

Solve for

y, x = \frac{1}{4} (y + 3)^{2} - 2

2 x + 2 - 3, - 2 x + 2 - 3

\frac{2 x - 3}{3 x - 1}

f (x) = 2 π r^{2} + 12 π r

f (x) = - (x - 5)^{2}

f (x) = \frac{e ^{x}}{e ^{x} + 2}

f (x) = 2 π r^{2} + 16 π r

What is the inverse of f(x)= 1/4 (x+3)^2-2 ?
The inverse of f(x)= 1/4 (x+3)^2-2 is 2sqrt(x+2)-3,-2sqrt(x+2)-3