What is the f(x)=(5x^3-3x^2+20x-12)/(|3-5x|) ?

The f(x)=(5x^3-3x^2+20x-12)/(|3-5x|) is

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f(x)=(5x^3-3x^2+20x-12)/(|3-5x|)

f (x) = \frac{5 x ^{3} - 3 x ^{2} + 20 x - 12}{∣ 3 - 5 x ∣}

Domain : x < \frac{3}{5} or x > \frac{3}{5}

Range : f (x) \leq - 4 or f (x) > \frac{109}{25}

Y Intercepts : (0, - 4)

Asymptotes : None

Extreme Points : Maximum (0, - 4)

Interval Notation

Domain : (- \infty, \frac{3}{5}) \cup (\frac{3}{5}, \infty)

Range : (- \infty, - 4] \cup (\frac{109}{25}, \infty)

Solution steps

Domain of

\frac{5 x ^{3} - 3 x ^{2} + 20 x - 12}{∣ 3 - 5 x ∣} : x < \frac{3}{5} or x > \frac{3}{5}

Range of

\frac{5 x ^{3} - 3 x ^{2} + 20 x - 12}{∣ 3 - 5 x ∣} : f (x) \leq - 4 or f (x) > \frac{109}{25}

Axis interception points of

\frac{5 x ^{3} - 3 x ^{2} + 20 x - 12}{∣ 3 - 5 x ∣} :

Y Intercepts

: (0, - 4)

Asymptotes of

\frac{5 x ^{3} - 3 x ^{2} + 20 x - 12}{∣ 3 - 5 x ∣} :

None

Extreme Points of

\frac{5 x ^{3} - 3 x ^{2} + 20 x - 12}{∣ 3 - 5 x ∣} :

Maximum

(0, - 4)

f (a) = 4 a^{4}

f (x) = \frac{2 ∣ x ∣ - 3}{x ^{2} + 1}

F (x) = \frac{2 x ^{2} + 3 x}{x - 1}

R (x, y, s) = \frac{( x , y )}{y} = 2 x + 1

f (x) = 13 - 2 x

What is the f(x)=(5x^3-3x^2+20x-12)/(|3-5x|) ?
The f(x)=(5x^3-3x^2+20x-12)/(|3-5x|) is