What is the f(x)= 2/(x+2)+(1-sqrt(9-x^2))/((x-3)-1) ?

The f(x)= 2/(x+2)+(1-sqrt(9-x^2))/((x-3)-1) is

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f(x)= 2/(x+2)+(1-sqrt(9-x^2))/((x-3)-1)

f (x) = \frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{( x - 3 ) - 1}

Domain : - 3 \leq x < - 2 or - 2 < x \leq 3

Range : f (x) \leq - 2.12780 \dots or f (x) \geq - \frac{3}{5}

X Intercepts : (2.94473 \dots, 0), Y Intercepts : (0, \frac{3}{2})

Asymptotes : Vertical x = - 2

Extreme Points : Minimum (- 3, - \frac{15}{7}), Maximum (- 2.99269 \dots, - 2.12780 \dots), Minimum (3, - \frac{3}{5})

Solution steps

Domain of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{x - 3 - 1} : - 3 \leq x < - 2 or - 2 < x \leq 3

Range of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{x - 3 - 1} : f (x) \leq - 2.12780 \dots or f (x) \geq - \frac{3}{5}

Axis interception points of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{x - 3 - 1} :

X Intercepts

: (2.94473 \dots, 0),

Y Intercepts

: (0, \frac{3}{2})

Asymptotes of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{x - 3 - 1} :

Vertical

: x = - 2

Extreme Points of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{x - 3 - 1} :

Minimum

(- 3, - \frac{15}{7}),

Maximum

(- 2.99269 \dots, - 2.12780 \dots),

Minimum

(3, - \frac{3}{5})

y = c^{1} + c^{2} e^{4} x

f (x) = x (2^{x})

f (a) = \frac{4 a ^{3} - a ^{2} + a - 2}{a}

f (x) = \frac{4}{9 x ^{2}}

f (x) = 2 x^{3} + x^{2} + 2 x

What is the f(x)= 2/(x+2)+(1-sqrt(9-x^2))/((x-3)-1) ?
The f(x)= 2/(x+2)+(1-sqrt(9-x^2))/((x-3)-1) is