What is the tangent of f(x)=(4x)/(x+2),(6,3) ?

The tangent of f(x)=(4x)/(x+2),(6,3) is y= 1/8 x+9/4

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tangent of f(x)=(4x)/(x+2),(6,3)

tangent of

f (x) = \frac{4 x}{x + 2}, (6, 3)

y = \frac{1}{8} x + \frac{9}{4}

Solution steps

Find the slope of

f (x) = \frac{4 x}{x + 2} : \frac{df ( x )}{d x} = \frac{8}{( x + 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(6, 3) : y = \frac{1}{8} x + \frac{9}{4}

y = \frac{1}{8} x + \frac{9}{4}

d er i v a t i v e f (x) = x^{2} + 5 x

\frac{d}{d x} (e^{l n (x^{2} + 1) + x})

\int_{- 1}^{6} \frac{9 y}{y ^{2} - 5 y - 14} d y

\int_{1}^{2} (\frac{4}{x} - \frac{16}{x ^{2}}) d x

y^{^{'}} - 2 t y = t

What is the tangent of f(x)=(4x)/(x+2),(6,3) ?
The tangent of f(x)=(4x)/(x+2),(6,3) is y= 1/8 x+9/4