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Popular Calculus >

y^'-2ty=t

Solution

y^{^{'}} - 2 t y = t

Solution

y = \frac{e ^{t^{2} + c_{1}}}{2} - \frac{1}{2}

Solution steps

y^{'} (t) - 2 t y = t

Solve separable ODE:

y = \frac{e ^{t^{2} + c_{1}}}{2} - \frac{1}{2}

y = \frac{e ^{t^{2} + c_{1}}}{2} - \frac{1}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'-2ty=t ?
The solution for y^'-2ty=t is y=(e^{t^2+c_{1}})/2-1/2