integral of sec^2(x)+9

Lösung

\int sec^{2} (x) + 9 d x

tan (x) + 9 x + C

Schritte zur Lösung

\int sec^{2} (x) + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x + \int 9 d x

\int sec^{2} (x) d x = tan (x)

\int 9 d x = 9 x

= tan (x) + 9 x

Füge eine Konstante zur Lösung hinzu

= tan (x) + 9 x + C

\int - \frac{5 ^{- x}}{ln ( 5 )} d x

\int - 36 x^{2} - 18 x - 4 d x

y^{^{''}} + 2 y^{^{'}} - 8 y = 2 e^{- 3 x} - e^{- x}

n = 0 \sum \infty (x - 2)^{n}

\frac{\partial}{\partial y} (e^{- x} sin (y) z)