integral from 1 to 6 of x^3ln(4x)

Lösung

\int_{1}^{6} x^{3} ln (4 x) d x

324 ln (24) - \frac{1295}{16} - \frac{1}{2} ln (2)

Dezimale

948.40536 \dots

Schritte zur Lösung

\int_{1}^{6} x^{3} ln (4 x) d x

Wende die partielle Integration an

= [\frac{1}{4} x^{4} ln (4 x) - \int \frac{x ^{3}}{4} d x]_{1}^{6}

\int \frac{x ^{3}}{4} d x = \frac{x ^{4}}{16}

= [\frac{1}{4} x^{4} ln (4 x) - \frac{x ^{4}}{16}]_{1}^{6}

Berechne die Grenzen:

324 ln (24) - \frac{1295}{16} - \frac{1}{2} ln (2)

= 324 ln (24) - \frac{1295}{16} - \frac{1}{2} ln (2)

in v erse l a pl a ce \frac{( s + 1 )}{( s + 2 ) ^{2}}

\int \frac{1}{( x - 2 ) ( x ^{2} + 4 )} d x

\frac{d}{d t} (cos^{3} (t) + sin^{3} (t))

\frac{\partial}{\partial z} (3 e^{x} cos (yz))

y^{^{''}} + a y = 0