(cos^2(t))^'

Lösung

(cos^{2} (t))^{^{'}}

- sin (2 t)

Schritte zur Lösung

(cos^{2} (t))^{'}

Wende die Kettenregel an:

2 cos (t) (cos (t))^{'}

= 2 cos (t) (cos (t))^{'}

(cos (t))^{'} = - sin (t)

= 2 cos (t) (- sin (t))

Vereinfache

2 cos (t) (- sin (t)) : - sin (2 t)

= - sin (2 t)

\frac{d}{d x} (9 x^{7} + 3 x^{5} - 6 x^{6} - 2 x^{4})

\frac{d}{d x} (5 x^{2} + 7 x - 6)

d er i v a t i v e 10 x \cdot e^{x}

\int_{0}^{1} 1.5 x^{2} d x

\frac{\partial}{\partial s} (2 s^{2} t^{2})