What is area y=e^x,y=e^{2x},x=ln(4) ?

The answer to area y=e^x,y=e^{2x},x=ln(4) is 9/2

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area y=e^x,y=e^{2x},x=ln(4)

area

y = e^{x}, y = e^{2 x}, x = ln (4)

\frac{9}{2}

Decimal

4.5

Solution steps

Apply the area formula:

\int_{0}^{l n (4)} e^{x} - e^{2 x} d x

Solve

\int_{0}^{l n (4)} e^{x} - e^{2 x} d x : \frac{9}{2}

The area is:

= \frac{9}{2}

(cos (\frac{1}{x}))^{^{'}}

\int \frac{30 x ^{2} - 49}{x ^{4}} d x

\frac{\partial}{\partial x} (\frac{x}{x - 1})

x \to 0 lim (2 x^{2} cos (\frac{5}{x}))

\frac{d y}{d x} = \frac{y}{x} + 5 x + 4

What is area y=e^x,y=e^{2x},x=ln(4) ?
The answer to area y=e^x,y=e^{2x},x=ln(4) is 9/2