What is the integral of (sqrt(1-x^2))/(x^2) ?

The integral of (sqrt(1-x^2))/(x^2) is -(sqrt(1-x^2))/x-arcsin(x)+C

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integral of (sqrt(1-x^2))/(x^2)

\int \frac{1 - x ^{2}}{x ^{2}} d x

- \frac{1 - x ^{2}}{x} - arcsin (x) + C

Solution steps

\int \frac{1 - x ^{2}}{x ^{2}} d x

Apply Integration By Parts

: - \frac{1 - x ^{2}}{x} - \int \frac{1}{1 - x ^{2}} d x

= - \frac{1 - x ^{2}}{x} - \int \frac{1}{1 - x ^{2}} d x

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= - \frac{1 - x ^{2}}{x} - arcsin (x)

Add a constant to the solution

= - \frac{1 - x ^{2}}{x} - arcsin (x) + C

\int \frac{2}{( x - 3 ) ( x + 1 )} d x

\int_{1}^{\infty} \frac{9}{x ^{2} + 1} d x

\int (4 x + 3) (2 x^{2} + 3 x)^{3} d x

\int \frac{1}{6 ( x ^{2} + 1 )} d x

f (x) = sin (e^{2 x})

What is the integral of (sqrt(1-x^2))/(x^2) ?
The integral of (sqrt(1-x^2))/(x^2) is -(sqrt(1-x^2))/x-arcsin(x)+C