y^'+y=2e^x

Lösung

y^{^{'}} + y = 2 e^{x}

y = e^{x} + \frac{c _{1}}{e ^{x}}

Schritte zur Lösung

y^{'} (x) + y = 2 e^{x}

Solve linear ODE:

y = e^{x} + \frac{c _{1}}{e ^{x}}

y = e^{x} + \frac{c _{1}}{e ^{x}}

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