y^'=e^{-3x}

Lösung

y^{^{'}} = e^{- 3 x}

y = - \frac{1}{3} e^{- 3 x} + c_{1}

Schritte zur Lösung

y^{'} (x) = e^{- 3 x}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int e^{- 3 x} d x

\int e^{- 3 x} d x = - \frac{1}{3} e^{- 3 x} + c_{1}

y = - \frac{1}{3} e^{- 3 x} + c_{1}

x \to 5 lim (\frac{∣ x - 5 ∣}{x - 5})

\int_{1}^{5} x^{2} ln (x) d x

in v erse l a pl a ce 1 - \frac{1}{1 + x}

\frac{d}{d x} (4 x^{2} 5 x + 1)

\int \frac{5}{4 sin ( x ) + 3 cos ( x )} d x