What is the derivative of (8x-6)^2 ?

The derivative of (8x-6)^2 is 16(8x-6)

What is the first derivative of (8x-6)^2 ?

The first derivative of (8x-6)^2 is 16(8x-6)

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derivative of

(8 x - 6)^{2}

16 (8 x - 6)

Solution steps

\frac{d}{d x} ((8 x - 6)^{2})

Apply the chain rule:

2 (8 x - 6) \frac{d}{d x} (8 x - 6)

= 2 (8 x - 6) \frac{d}{d x} (8 x - 6)

\frac{d}{d x} (8 x - 6) = 8

= 2 (8 x - 6) \cdot 8

Simplify

= 16 (8 x - 6)

\int (\frac{x ^{2} + 5}{( x + 2 ) ^{2}}) d x

\int \frac{x ^{3}}{x + 2} d x

l a pl a ce t r an s f or m sin (2 x + 3)

x \to 0 lim (x^{3} cos (\frac{5}{x}))

\frac{\partial}{\partial y} (\frac{x}{y + 1})

What is the derivative of (8x-6)^2 ?
The derivative of (8x-6)^2 is 16(8x-6)
What is the first derivative of (8x-6)^2 ?
The first derivative of (8x-6)^2 is 16(8x-6)