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Popular Calculus >

integral from 1 to 2 of (7x+x^2)

Solution

\int_{1}^{2} (7 x + x^{2}) d x

Solution

\frac{77}{6}

+1

Decimal

12.83333 \dots

Solution steps

\int_{1}^{2} 7 x + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 7 x d x + \int_{1}^{2} x^{2} d x

\int_{1}^{2} 7 x d x = \frac{21}{2}

\int_{1}^{2} x^{2} d x = \frac{7}{3}

= \frac{21}{2} + \frac{7}{3}

Simplify

\frac{21}{2} + \frac{7}{3} : \frac{77}{6}

= \frac{77}{6}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (7x+x^2) ?
The integral from 1 to 2 of (7x+x^2) is 77/6