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Popular Calculus >

y^'=e(-2t)-y

Solution

y^{^{'}} = e (- 2 t) - y

Solution

y = - 2 e (t - 1) + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) = e (- 2 t) - y

Solve linear ODE:

y = - 2 e (t - 1) + \frac{c _{1}}{e ^{t}}

y = - 2 e (t - 1) + \frac{c _{1}}{e ^{t}}

Graph

Popular Examples

(cos (3 x))^{^{'}}

derivative of e^x-1-x

\frac{d}{d x} (e^{x} - 1 - x)

(dy)/(dx)=e^{-x^2}

\frac{d y}{d x} = e^{- x^{2}}

(\partial)/(\partial x)((x-y)/(x^2+y+1))

\frac{\partial}{\partial x} (\frac{x - y}{x ^{2} + y + 1})

integral from 0 to 3 of (2-x)e^x

\int_{0}^{3} (2 - x) e^{x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=e(-2t)-y ?
The solution for y^'=e(-2t)-y is y=-2e(t-1)+(c_{1})/(e^t)