What is the first derivative of 4e^0 ?

The first derivative of 4e^0 is 0

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derivative of 4e^0

\frac{d}{d x} (4 e^{0})

0

Solution steps

\frac{d}{d x} (4 e^{0})

4 e^{0} = 4

= \frac{d}{d x} (4)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

t a y l or sin (\frac{x}{2}), π

d er i v a t i v e \frac{1}{x ^{2} - 1}

\int e^{1} d x

d er i v a t i v e arctan (\frac{1 + x}{1 - x})

y^{^{''}} - 3 y^{^{'}} + 2 y = 2 e^{t}