What is the derivative of 1/(x^2-1) ?

The derivative of 1/(x^2-1) is -(2x)/((x^2-1)^2)

What is the first derivative of 1/(x^2-1) ?

The first derivative of 1/(x^2-1) is -(2x)/((x^2-1)^2)

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derivative of

\frac{1}{x ^{2} - 1}

- \frac{2 x}{( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{2} - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x^{2} - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} - 1 ) ^{2}} \frac{d}{d x} (x^{2} - 1)

= - \frac{1}{( x ^{2} - 1 ) ^{2}} \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= - \frac{1}{( x ^{2} - 1 ) ^{2}} \cdot 2 x

Simplify

- \frac{1}{( x ^{2} - 1 ) ^{2}} \cdot 2 x : - \frac{2 x}{( x ^{2} - 1 ) ^{2}}

= - \frac{2 x}{( x ^{2} - 1 ) ^{2}}

\int e^{1} d x

d er i v a t i v e arctan (\frac{1 + x}{1 - x})

y^{^{''}} - 3 y^{^{'}} + 2 y = 2 e^{t}

\int cos (a) x d x

d er i v a t i v e x e^{y}

What is the derivative of 1/(x^2-1) ?
The derivative of 1/(x^2-1) is -(2x)/((x^2-1)^2)
What is the first derivative of 1/(x^2-1) ?
The first derivative of 1/(x^2-1) is -(2x)/((x^2-1)^2)