dr=e(rsin(θ)dθ-cos(θ)dr)

解答

d r = e (r sin (θ) d θ - cos (θ) d r)

θ = arccos (\frac{c _{1} - r}{er}) + 2 πn, θ = - arccos (\frac{c _{1} - r}{er}) + 2 πn

求解步骤

d r = e (r sin (θ) d θ - cos (θ) d r)

求解可分离方程:

θ = arccos (\frac{c _{1} - r}{er}) + 2 πn, θ = - arccos (\frac{c _{1} - r}{er}) + 2 πn

θ = arccos (\frac{c _{1} - r}{er}) + 2 πn, θ = - arccos (\frac{c _{1} - r}{er}) + 2 πn

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