(e^{-1/(x^2)})^'

Lösung

(e^{- \frac{1}{x ^{2}}})^{^{'}}

\frac{2 e ^{- \frac{1}{x ^{2}}}}{x ^{3}}

Schritte zur Lösung

(e^{- \frac{1}{x ^{2}}})^{'}

Wende die Kettenregel an:

e^{- \frac{1}{x ^{2}}} (- \frac{1}{x ^{2}})^{'}

= e^{- \frac{1}{x ^{2}}} (- \frac{1}{x ^{2}})^{'}

(- \frac{1}{x ^{2}})^{'} = \frac{2}{x ^{3}}

= e^{- \frac{1}{x ^{2}}} \frac{2}{x ^{3}}

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 e ^{- \frac{1}{x ^{2}}}}{x ^{3}}

\int \frac{e ^{x}}{e ^{2 x} + 1} d x

\int_{2}^{3} \frac{5}{3 - x} d x

\frac{\partial}{\partial x} (x^{2} \cdot y^{3})

\int x (x + a) (x + b) d x

y^{^{''}} + 20 y^{^{'}} + 500 = 12