What is the derivative of 8x^2+3x-2 ?

The derivative of 8x^2+3x-2 is 16x+3

What is the first derivative of 8x^2+3x-2 ?

The first derivative of 8x^2+3x-2 is 16x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (8 x^{2} + 3 x - 2)

16 x + 3

Solution steps

\frac{d}{d x} (8 x^{2} + 3 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 16 x + 3 - 0

Simplify

= 16 x + 3

a re a x^{3} - 3 x^{2} + 2 x, 0 \leq x \leq 2

d er i v a t i v e - 3 (e^{x})^{3}

a re a y = x^{4} - x^{2}, y = 1 - x^{2}

\frac{d}{d θ} (θ cos (θ) - sin (θ))

\frac{d}{d x} (e^{x + 2 y})

What is the derivative of 8x^2+3x-2 ?
The derivative of 8x^2+3x-2 is 16x+3
What is the first derivative of 8x^2+3x-2 ?
The first derivative of 8x^2+3x-2 is 16x+3