What is area x^3-3x^2+2x,0<= x<= 2 ?

The answer to area x^3-3x^2+2x,0<= x<= 2 is 1/2

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area x^3-3x^2+2x,0<= x<= 2

area

x^{3} - 3 x^{2} + 2 x, 0 \leq x \leq 2

\frac{1}{2}

Decimal

0.5

Solution steps

Apply the area formula:

\int_{0}^{2} x^{3} - 3 x^{2} + 2 x d x

Solve

\int_{0}^{2} x^{3} - 3 x^{2} + 2 x d x : \frac{1}{2}

The area is:

= \frac{1}{2}

- 3 (e^{x})^{3}

y = x^{4} - x^{2}, y = 1 - x^{2}

\frac{d}{d θ} (θ cos (θ) - sin (θ))

\frac{d}{d x} (e^{x + 2 y})

\frac{d}{d x} (ln (\frac{( 2 x - 1 )}{x - 1}))

What is area x^3-3x^2+2x,0<= x<= 2 ?
The answer to area x^3-3x^2+2x,0<= x<= 2 is 1/2