derivative of 1/(-2x^2)

解答

\frac{d}{d x} (\frac{1}{- 2 x ^{2}})

\frac{1}{x ^{3}}

求解步骤

\frac{d}{d x} (\frac{1}{- 2 x ^{2}})

化简

\frac{1}{- 2 x ^{2}} : - \frac{1}{2 x ^{2}}

= \frac{d}{d x} (- \frac{1}{2 x ^{2}})

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{2} \frac{d}{d x} (\frac{1}{x ^{2}})

使用指数法则:

\frac{1}{a} = a^{- 1}

= - \frac{1}{2} \frac{d}{d x} (x^{- 2})

使用幂法则:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{2} (- 2 x^{- 2 - 1})

化简

- \frac{1}{2} (- 2 x^{- 2 - 1}) : \frac{1}{x ^{3}}

= \frac{1}{x ^{3}}

n = 0 \sum \infty (2 x)^{n}

t an g e n t f (x) = x 2^{x}

s l o p e (- 2.3) (2.2)

x \to 0 - lim (x \cdot arctan (\frac{1}{x}))

\frac{d y}{d x} = \frac{2 x}{1 + 2 y}, y (2) = 0