(d^2y)/(dt^2)+5(dy)/(dt)+6y=1

解答

\frac{d ^{2} y}{d t ^{2}} + 5 \frac{d y}{d t} + 6 y = 1

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + \frac{1}{6}

求解步骤

\frac{d ^{2} y}{d t ^{2}} + 5 \frac{d y}{d t} + 6 y = 1

求解线性方程:

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + \frac{1}{6}

y = c_{1} e^{- 2 t} + c_{2} e^{- 3 t} + \frac{1}{6}

x y^{2} y^{^{'}} = y^{3} - 4 x^{3}, y (1) = 4

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