(\partial)/(\partial x)(sin(5xy+4yz+7xz))

Lösung

\frac{\partial}{\partial x} (sin (5 x y + 4 yz + 7 x z))

cos (5 x y + 4 yz + 7 x z) (5 y + 7 z)

Schritte zur Lösung

\frac{\partial}{\partial x} (sin (5 x y + 4 yz + 7 x z))

Behandle

y, z

als Konstanten

Wende die Kettenregel an:

cos (5 x y + 4 yz + 7 x z) \frac{\partial}{\partial x} (5 x y + 4 yz + 7 x z)

= cos (5 x y + 4 yz + 7 x z) \frac{\partial}{\partial x} (5 x y + 4 yz + 7 x z)

\frac{\partial}{\partial x} (5 x y + 4 yz + 7 x z) = 5 y + 7 z

= cos (5 x y + 4 yz + 7 x z) (5 y + 7 z)

t an g e n t f (x) = \frac{- 8 x}{x ^{2} + 1}, (0, 0)

\int e^{- \frac{1}{2} z^{2}}

\frac{d x}{d t} = 0.6 - \frac{5 x}{1000 + t}

d er i v a t i v e y = ln (x + 4)

x \to 0 lim (∣ e^{x} - 1 ∣)