7x(x+y)y^'=7y(x-y)

Lösung

7 x (x + y) y^{^{'}} = 7 y (x - y)

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

Schritte zur Lösung

7 x (x + y) y^{'} (x) = 7 y (x - y)

Solve using substitution:

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

\frac{\partial}{\partial x} (8 x^{0.5} y^{0.5})

\frac{d}{d x} (- \frac{2 ( - 3 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{3}})

t an g e n t f (x) = x^{3} - 4 x + 6, (2, 6)

d er i v a t i v e f (x) = x^{2} (2 + x^{- 3})

\frac{\partial}{\partial x} (x y^{2} - 2 x)