y^{''}+10y^'+25y=0,y(1)=0,y^'(1)=1

Lösung

y^{^{''}} + 10 y^{^{'}} + 25 y = 0, y (1) = 0, y^{^{'}} (1) = 1

y = - e^{5 - 5 t} + e^{5 - 5 t} t

Schritte zur Lösung

y^{''} (t) + 10 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = - e^{5 - 5 t} + e^{5 - 5 t} t

y = - e^{5 - 5 t} + e^{5 - 5 t} t

x \to 1 lim (- 1.6 x + 0.6)

\int \frac{1}{x ln ( 3 x )} d x

\frac{d}{d x} (\frac{ln ( x ) + 1}{ln ( x ) - 1})

x \to - 2 lim (\frac{2 - ∣ x ∣}{2 + x})

y^{^{'}} = 2 x y + x y^{2}