en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

y^'-e^{6x+y}=0

Solution

y^{^{'}} - e^{6 x + y} = 0

Solution

y = - ln (- \frac{1}{6} e^{6 x} - c_{1})

Solution steps

y^{'} (x) - e^{6 x + y} = 0

Solve separable ODE:

y = - ln (- \frac{1}{6} e^{6 x} - c_{1})

y = - ln (- \frac{1}{6} e^{6 x} - c_{1})

Graph

Popular Examples

integral of x(x+1)^4

\int x (x + 1)^{4} d x

(arcsin (2 x))^{^{'}}

y^{''}-9y=e^{3x}

y^{^{''}} - 9 y = e^{3 x}

derivative of {y}(θ,xtan(θ))

\frac{d}{d x} (y (θ, x) tan (θ))

y(dy)/(dx)-y^3=y^2ln(x)

y \frac{d y}{d x} - y^{3} = y^{2} ln (x)

Frequently Asked Questions (FAQ)

What is the solution for y^'-e^{6x+y}=0 ?
The solution for y^'-e^{6x+y}=0 is y=-ln(-1/6 e^{6x}-c_{1})