What is the tangent of f(x)= 1/(x^4),\at x=1 ?

The tangent of f(x)= 1/(x^4),\at x=1 is y=-4x+5

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tangent of f(x)= 1/(x^4),\at x=1

tangent of

f (x) = \frac{1}{x ^{4}}, at x = 1

y = - 4 x + 5

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{1}{x ^{4}} : \frac{df ( x )}{d x} = - \frac{4}{x ^{5}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(1, 1) : y = - 4 x + 5

y = - 4 x + 5

\int_{6}^{8} \frac{32}{( x - 6 ) ^{3}} d x

y^{^{'}} + y = e^{x} y^{2}

\int_{1}^{2} \frac{( 2 x + 1 ) ( x - 2 )}{x} d x

d er i v a t i v e f (x) = \frac{x}{x - 7}

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{7 + e ^{x}}

What is the tangent of f(x)= 1/(x^4),\at x=1 ?
The tangent of f(x)= 1/(x^4),\at x=1 is y=-4x+5