What is the integral of-3x^2-6x+45 ?

The integral of-3x^2-6x+45 is -x^3-3x^2+45x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of-3x^2-6x+45

\int - 3 x^{2} - 6 x + 45 d x

- x^{3} - 3 x^{2} + 45 x + C

Solution steps

\int - 3 x^{2} - 6 x + 45 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 3 x^{2} d x - \int 6 x d x + \int 45 d x

\int 3 x^{2} d x = x^{3}

\int 6 x d x = 3 x^{2}

\int 45 d x = 45 x

= - x^{3} - 3 x^{2} + 45 x

Add a constant to the solution

= - x^{3} - 3 x^{2} + 45 x + C

t an g e n t f (x) = \frac{1}{x ^{4}}, at x = 1

\int_{6}^{8} \frac{32}{( x - 6 ) ^{3}} d x

y^{^{'}} + y = e^{x} y^{2}

\int_{1}^{2} \frac{( 2 x + 1 ) ( x - 2 )}{x} d x

d er i v a t i v e f (x) = \frac{x}{x - 7}

What is the integral of-3x^2-6x+45 ?
The integral of-3x^2-6x+45 is -x^3-3x^2+45x+C