derivative of sqrt(2+cos(2x))

Lösung

\frac{d}{d x} (2 + cos (2 x))

- \frac{sin ( 2 x )}{2 + cos ( 2 x )}

Schritte zur Lösung

\frac{d}{d x} (2 + cos (2 x))

Wende die Kettenregel an:

\frac{1}{2 2 + cos ( 2 x )} \frac{d}{d x} (2 + cos (2 x))

= \frac{1}{2 2 + cos ( 2 x )} \frac{d}{d x} (2 + cos (2 x))

\frac{d}{d x} (2 + cos (2 x)) = - 2 sin (2 x)

= \frac{1}{2 2 + cos ( 2 x )} (- 2 sin (2 x))

Vereinfache

\frac{1}{2 2 + cos ( 2 x )} (- 2 sin (2 x)) : - \frac{sin ( 2 x )}{2 + cos ( 2 x )}

= - \frac{sin ( 2 x )}{2 + cos ( 2 x )}

p a r t ia l f r a c t i o n \frac{x}{x ^{2} - 9}

\frac{d}{d y} (sinh (y))

im pl i c i t x^{2} + 11 x y + y^{2} = 11

x (x^{3} + 1) y^{^{'}} + (2 x^{3} - 1) y = \frac{( x ^{3} - 2 )}{x}

\frac{d}{d x} (3 lo g_{10} (x))