y^'+y=5cos(2t)

Lösung

y^{^{'}} + y = 5 cos (2 t)

y = 2 sin (2 t) + cos (2 t) + \frac{c _{1}}{e ^{t}}

Schritte zur Lösung

y^{'} (t) + y = 5 cos (2 t)

Solve linear ODE:

y = 2 sin (2 t) + cos (2 t) + \frac{c _{1}}{e ^{t}}

y = 2 sin (2 t) + cos (2 t) + \frac{c _{1}}{e ^{t}}

in v erse l a pl a ce \frac{( 3 s + 7 )}{s ^{2} + 4 s + 3}

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